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4n^2-43n-60=0
a = 4; b = -43; c = -60;
Δ = b2-4ac
Δ = -432-4·4·(-60)
Δ = 2809
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2809}=53$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-43)-53}{2*4}=\frac{-10}{8} =-1+1/4 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-43)+53}{2*4}=\frac{96}{8} =12 $
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